# Solving Algebra Problems Step By Step Either method works, so do whichever you like most.I stuck with just solving the equation that was in the parenthesis: 30/3=10.So in order to do that, let's get rid of this 2.

Either method works, so do whichever you like most.I stuck with just solving the equation that was in the parenthesis: 30/3=10.

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I have solved for the x that satisfies this equation. I divided both sides by five, so this right over here is step two.

I added 11 to both sides then divide both sides by five. I'm going to add 11 to both sides, adding 11 to both sides then I'm just left with 5x is equal to 53 and then I divide both sides by five.

All of these mean the exact same thing: 2 times 10. In algebra, we do this thing called "combining like terms." This means that we see 17-55 as a 17 and -55.

In algebra, however, the variable "x" is quite common, so you may want to stop using that form. We just add those, and the rest of the numbers up in a calculator to get the next answer.

Voiceover: Create a list of steps, in order, that will solve the following equation.

It gives the equation here then they have a bunch of steps that they want us to put in order. You might be able to work this out in your head eventually but I'll do it on this scratch pad first.The best way to get this minus, get rid of that minus 11 on the left hand side is to add 11 to the left hand side but I can't just do it only to the left hand side, then these two things won't be equal anymore.In order for them to both be equal, I have to do the same thing to both sides. Well I added 11 to both sides, so this is going to be my first step. Once again I want this to be on the form of x equals something that I know what x is.The first thing you do when solving an algebra problem is write the problem and the steps down. The acronym PEMDAS is something you will use every time you work with equations.Teachers love seeing the steps and it makes it easier to catch mistakes. It stands for Parenthesis, Exponents, Multiply, Divide, Add, and Subtract.There are no exponents in this problem, but I drew one so you could see what one looks like.When dealing with exponents, you donot multiply the big number by the little one.So we can multiply that by 4, but once again, this is an equation. If we were to multiply 18 times 4, 4 times 8 is 32. But this is negative 18 times 4, so it's negative 72. And if we want to check it, we can just substitute it back into that original equation. Let's substitute this into the original equation. Anything you do to the right-hand side, you have to do to the left-hand side, and vice versa. So the original equation was negative 16 is equal to-- instead of writing x, I'm going to write negative 72-- is equal to negative 72 over 4 plus 2. So this right-hand side simplifies to negative 72 divided by 4. I could write just a plus 0, but I think that's a little unnecessary. And our whole goal here is to isolate the x, to solve for the x.And the best way we can do that, if we have x over 4 here, if we multiply that by 4, we're just going to have an x. And then the right-hand side, negative 18 plus 2, that's negative 16. This right-hand side, when x is equal to negative 72, does indeed equal negative 16.

## Comments Solving Algebra Problems Step By Step

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